如何判断2次点击的节点名字一样

@826288352 写道：

我想做连连看的效果

页面加载的时候能判断当前节点是哪个 ，下次点击的时候会输出下次的节点名字，我如果判断这2个节点一样，从而使这2个节点消除
game.js是加载在canvas上的插件,bgPrefab是红色背景预制模板aabbcc分别是连连看的小图；
以下是game.js：


cc.Class({
extends: cc.Component,
properties: {
bgPrefab: {
default: null,
type: cc.Prefab
},
draw: {
default: null,
type: cc.Node
},
imgWidth:58,
imgHeight:52,

},

// use this for initialization
onLoad: function () {
   var x1;
   var y1;
   this.addMouse();
},

// called every frame, uncomment this function to activate update callback
 update: function (dt) {
     
 },
newredbg: function(x1,y1) {
    var newbg = cc.instantiate(this.bgPrefab);
    this.node.addChild(newbg);
    newbg.setPosition(x1,y1);
 },
 removeBg:function(){
   //console.log(this.node.children);
    this.node.children[this.node.children.length-1].destroy();
 },
addMouse:function(){
    var imgWidth=this.imgWidth;
    var imgHeight=this.imgHeight;
    this.node.on('touchstart', function (event) {
       var x1= event.getLocationX()-480;
       var y1= event.getLocationY()-320;
       if(this.node.children[this.node.children.length-1].name!="bg"){
              if(x1>-imgWidth/2&&x1<imgWidth/2&&y1>-imgHeight/2&&y1<imgHeight/2){
                  this.newredbg(0,0);
                  console.log(this.node.name);
              }
              else if(x1>-imgWidth/2&&x1<imgWidth/2&&y1>imgHeight/2&&y1<imgHeight*3/2){
                  this.newredbg(0,imgHeight);
              }
              else if(x1>-imgWidth/2&&x1<imgWidth/2&&y1>-imgHeight*3/2&&y1<-imgHeight/2){
                  console.log(imgHeight);
                  this.newredbg(0,-imgHeight);
              }
              else if(x1>-(imgWidth)*3/2&&x1<-imgWidth/2&&y1>-imgHeight/2&&y1<imgHeight/2){
                  this.newredbg(-imgWidth,0);
              }
              else if(x1>-(imgWidth)*3/2&&x1<-imgWidth/2&&y1>imgHeight/2&&y1<imgHeight*3/2){
                   this.newredbg(-imgWidth,imgHeight);
              }
              else if(x1>-(imgWidth)*3/2&&x1<-imgWidth/2&&y1>-imgHeight*3/2&&y1<-imgHeight/2){
                  this.newredbg(-imgWidth,-imgHeight);
              }
              
        }else{
            this.removeBg();
       }
        
     }, this);
},

});

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